Determine C:H ratio from combustion analysis Steps:

• Moles of CO₂ = 1.32 g / 44 g/mol = 0.03 mol, so 0.03 mol C atoms.
• Moles of H₂O = 0.54 g / 18 g/mol = 0.03 mol, so 0.06 mol H atoms (2 H per H₂O).
• Atomic ratio C:H = 0.03:0.06 = 1:2, so empirical formula CH₂.
• Match to molecular formulas: only option with 1:2 C:H ratio fits the data. Why B is correct:
• CH₃CH=CH₂ (propene, C₃H₆) has 3:6 = 1:2 C:H ratio, matching the combustion products per the balanced equation C₃H₆ + 4.5 O₂ → 3 CO₂ + 3 H₂O. Why the others are wrong:
• A: CH₃CH₂CH₃ (propane, C₃H₈) has 3:8 C:H ratio, yielding more H₂O than observed.
• C: CH₃C≡CH (propyne, C₃H₄) has 3:4 C:H ratio, yielding less H₂O than observed.
• D: Not enough information.

Final answer: B