A Levels Chemistry (9701)•9701/13/M/J/18

Explanation
Esterification mismatch between given acid and ester structure
Steps:
- Parse the ester formula CH3CH2COOCH3 as CH3CH2C(=O)OCH3, identifying it as methyl propanoate (from propanoic acid CH3CH2COOH and methanol CH3OH).
- Note the preparation uses ethanoic acid (CH3COOH), which produces ethanoate esters CH3C(=O)OR, not propanoates.
- Recognize the inconsistency: the reaction with ethanoic acid cannot yield a propanoate ester.
- Conclude no alcohol Y fits both the ester structure and the specified reaction.
Why B is correct:
- Not applicable due to mismatch; no option produces the given ester with ethanoic acid.
Why the others are wrong:
- A, C, D: All yield ethanoate esters with ethanoic acid, but none match CH3CH2C(=O)OCH3.
Not enough information. Final answer: Not enough information.
Topic: Carboxylic acids and derivatives
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