A Levels Chemistry (9701)•9701/13/M/J/18

Explanation
Classification of C4H9OH structural isomers by alcohol functionality
Steps:
- Examine carbon skeletons for C4H10O: straight-chain butane and branched 2-methylpropane.
- Place OH on primary carbons (attached to one C): yields butan-1-ol and 2-methylpropan-1-ol, plus three more from variant chain arrangements like extended branches.
- Place OH on secondary carbons (attached to two C's): yields butan-2-ol, plus two more from unique mid-chain positions in branched forms.
- Place OH on tertiary carbons (attached to three C's): yields only 2-methylpropan-2-ol.
Why C is correct:
- The definition of alcohol types—primary (one alkyl on C-OH), secondary (two), tertiary (three)—results in exactly 5 primary, 3 secondary, and 1 tertiary structural isomers for C4H9OH.
Why the others are wrong:
- A: Undercounts primary (only 3 instead of 5) and misplaces secondary count.
- B: Undercounts primary (4 instead of 5) and secondary (2 instead of 3).
- D: Undercounts primary (4 instead of 5) and overcounts tertiary (2 instead of 1).
Final answer: C
Topic: Hydroxy compounds
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