Equilibrium positions determine relative K magnitudes Steps:

• K1 and K2 equilibria lie left, so K1 << 1 and K2 << 1 (low solubility).
• K3 equilibrium lies right, so K3 >> 1 (favors dissociation).
• AgCl dissolves in NH3 but AgI does not, implying K1 > K2 since complex formation (same for both) drives solubility more for larger Ksp.
• Direct comparison from positions: large K3 exceeds small K1.

Why C is correct:

• Equilibrium position right for K3 means K3 > 1; left for K1 means K1 < 1; thus K3 > K1 by definition.

Why the others are wrong:

• A: Implied by solubility difference (K1 > K2), but not direct from positions of all three.
• B: Contradicts solubility; AgCl dissolves more, so K1 > K2, not reverse.
• D: Impossible; small K1 cannot exceed large K3.

Final answer: C