A Levels Chemistry (9701)•9701/11/M/J/18

Explanation
Ester Hydrolysis and Re-esterification Steps:
- Ethyl propanoate (CH₃CH₂C(O)OCH₂CH₃) undergoes basic hydrolysis with aqueous NaOH to yield sodium propanoate and ethanol (CH₃CH₂OH).
- The alcohol produced is ethanol.
- Ethanol reacts with propanoic acid (CH₃CH₂COOH) via esterification to form the ester CH₃CH₂C(O)OCH₂CH₃.
- This second ester is ethyl propanoate, matching option A.
Why A is correct:
- A depicts CH₃CH₂OC(O)CH₂CH₃, the formula for ethyl propanoate from esterification of ethanol and propanoic acid.
Why the others are wrong:
- B shows CH₃CH₂CH₂OC(O)CH₃ (propyl acetate), using propanol instead of ethanol.
- C shows CH₃C(O)OCH(CH₃)CH₃ (isopropyl acetate), using isopropanol and acetic acid.
- D shows CH₃CH₂C(O)OCH(CH₃)CH₃ (isopropyl propanoate), using isopropanol instead of ethanol.
Final answer: A
Topic: Carboxylic acids and derivatives
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