mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
A Levels Biology (9700)•9700/13/O/N/24
Question 11 from 9700/13/O/N/24

Explanation

Km as Substrate Concentration at Half Vmax

Steps:

  • Identify Vmax as the maximum rate on the graph's plateau.
  • Calculate half Vmax (Vmax/2).
  • Locate the substrate concentration [S] where the rate equals Vmax/2 on the curve.
  • This [S] value is Km, reading 2 mol dm^{-3} from the graph.

Why A is correct:

  • Km is defined in the Michaelis-Menten equation as the [S] at which reaction rate reaches half Vmax.

Why the others are wrong:

  • B: 5 mol dm^{-3} corresponds to a rate above Vmax/2 on the curve.
  • C: 30 mol dm^{-3} is a high [S] near Vmax, not half.
  • D: 50 mol dm^{-3} exceeds the half-rate point, approaching saturation.

Final answer: A

Topic: Factors that affect enzyme action

Practice more A Levels Biology (9700) questions on mMCQ.me