Account for water loss in phospholipid ester bonds

Steps:

• Calculate one phospholipid: glycerol (92 g/mol) + 2 fatty acids (2 × 282 = 564 g/mol) + phosphate (95 g/mol) = 751 g/mol.
• Subtract 3 H₂O (3 × 18 = 54 g/mol) lost in forming three ester bonds (two with fatty acids, one with phosphate): 751 - 54 = 697 g/mol.
• For six molecules: 6 × 697 = 4182 g/mol.

Why B is correct:

• Matches the formula for phospholipid molecular weight: sum of components minus 3 H₂O for esterification, per standard organic chemistry.

Why the others are wrong:

• A: Underestimates by ignoring full components or over-subtracting water.
• C: Forgets to subtract water loss, giving 6 × 751 ≈ 4506 (rounded to 4505).
• D: Overestimates, possibly adding extra components or no subtractions.

Final answer: B