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A Levels Biology (9700)•9700/13/O/N/22
Question 36 from 9700/13/O/N/22

Explanation

Chloride-bicarbonate shift maximizes ions in RBCs at high PCO2 and low PO2

Steps:

  • CO2 diffuses into RBCs and converts to HCO3- and H+ via carbonic anhydrase, increasing intracellular ions.
  • HCO3- exits RBCs via band 3 exchanger, importing Cl- ions (chloride shift), further elevating RBC ion concentration.
  • This shift is enhanced by high PCO2, which right-shifts the O2 dissociation curve (Bohr effect), promoting O2 unloading.
  • Maximum ions occur where high PCO2 meets low PO2, as in tissues, corresponding to the right-shifted curve's lower saturation point.

Why B is correct:

  • Position B lies on the high PCO2 curve at low PO2, where CO2 loading drives maximal HCO3-/Cl- exchange per the chloride shift mechanism.

Why the others are wrong:

  • A: On low PCO2 curve, minimal CO2 conversion limits ion influx.
  • C: High saturation on high PCO2 curve means less O2 unloading, reducing shift efficiency.
  • D: On low PCO2 curve at high PO2, negligible CO2 effect keeps ions low.

Final answer: B

Topic: Transport of oxygen and carbon dioxide

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