A Levels Biology (9700)•9700/12/O/N/22

Explanation
Glycosidic bond identification by linkage position and anomeric configuration
Steps:
- Locate the bond at position X, which connects the anomeric carbon (C1) of one monosaccharide to another in the polysaccharide chain.
- Assess the anomeric configuration: alpha if the OH group at C1 is below the ring plane in the Haworth projection.
- Identify the attachment point on the second monosaccharide: position 6 indicates linkage to the CH2OH group carbon.
- Confirm the bond as α-1,6 based on alpha orientation and C6 linkage in the diagram.
Why B is correct:
- α-1,6 glycosidic bonds form between C1 (alpha) of one glucose and C6 of another, creating branched structures like in glycogen, matching the diagram's configuration.
Why the others are wrong:
- A links C1 (alpha) to C4, forming linear chains like in starch, not branching at C6.
- C links C1 (beta) to C4, as in cellulose, with beta orientation not shown.
- D links C1 (beta) to C6, rare in polysaccharides and mismatches the alpha configuration.
Final answer: B
Topic: Carbohydrates and lipids
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