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A Levels Biology (9700)•9700/12/O/N/20
Question 7 from 9700/12/O/N/20

Explanation

Boiled diastase fails to hydrolyze starch

Steps:

  • Boiling denatures diastase, inactivating the enzyme.
  • Untreated starch remains intact after 15 minutes.
  • Iodine reacts with starch to produce blue-black color.
  • Benedict's reagent detects no reducing sugars, staying blue.

Why A is correct:

  • Inactivated enzyme leaves starch unchanged, yielding blue-black with iodine (starch test) and blue with Benedict's (no reducing maltose).

Why the others are wrong:

  • B: Benedict's red indicates reducing sugar, but no maltose forms.
  • C: Iodine brown suggests absent starch, but starch persists.
  • D: Iodine brown wrongly implies starch breakdown.

Final answer: A

Topic: Factors that affect enzyme action

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