Km inversely relates to substrate affinity Steps:

• Identify Km values: Enzyme C has Km = 1.5 × 10² = 150 (arbitrary units); enzyme P has Km = 5.0 × 10³ = 5,000.
• Recall that Km is the substrate concentration for half Vmax; lower Km indicates higher enzyme-substrate affinity.
• Compare values: Enzyme C's lower Km (150) means higher affinity than enzyme P's (5,000).
• Conclude the correct interpretation states the enzyme with lowest Km has greatest affinity.

Why C is correct:

• Lower Km reflects greater substrate affinity per Michaelis-Menten kinetics, so enzyme C binds substrate more tightly than P.

Why the others are wrong:

• A: Incomplete and unclear; does not interpret Km values or affinity.
• B: Refers to Vmax (not in table); Km does not determine Vmax.
• D: Enzyme P's Km is 5,000, not 10 mmol/L; units and value mismatch.

Final answer: C