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A Levels Biology (9700)•9700/13/M/J/23
Question 10 from 9700/13/M/J/23

Explanation

Comparing carbon chain lengths in triglycerides Steps:

  • Recall fatty acid carbons: palmitic (P) = 16C, oleic (O) = 18C, stearic (S) = 18C.
  • Compute total carbons for SOS: S + O + S = 18 + 18 + 18 = 54C.
  • Compute total carbons for POP: P + O + P = 16 + 18 + 16 = 50C.
  • Subtract: 54 - 50 = 4 more carbons in SOS than POP.

Why C is correct:

  • Total fatty acid carbons define chain length; SOS uses three 18C acids (54C) vs. POP's two 16C and one 18C (50C), yielding a 4C difference.

Why the others are wrong:

  • A: POS has one unsaturated acid (O), not two.
  • B: POS totals 52C (P + O + S), more than POP's 50C.
  • D: Acids join glycerol via ester bonds, not hydrolysis (which cleaves them).

Final answer: C

Topic: Carbohydrates and lipids

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