A Levels Biology (9700)•9700/11/M/J/22

Explanation
Properties of triglycerides X, Y, and Z based on fatty acid saturation
Steps:
- Examine diagrams: X has all single bonds in chains (saturated), Y has one double bond (monounsaturated), Z has multiple double bonds (polyunsaturated).
- Identify saturation: X is fully saturated, Y and Z unsaturated.
- Classify by type: All are triglycerides with glycerol and three fatty acids; X and Y have even-numbered chains, Z odd.
- Match to query parts: All have fatty acids; Y and Z unsaturated; X and Y solid at room temp; Z liquid.
Why A is correct:
- Matches definitions: Saturated fats (X) lack double bonds (straight chains pack tightly); unsaturated (Y, Z) have double bonds (kinks prevent packing), per lipid structure rules.
Why the others are wrong:
- B: Incorrectly groups X and Y as unsaturated starters, ignoring X's saturation.
- C: Overincludes Z as saturated and misgroups solids.
- D: Reverses saturation and solid groups, violating chain packing principles.
Final answer: A
Topic: Carbohydrates and lipids
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