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A Levels Biology (9700)•9700/11/M/J/22
Question 6 from 9700/11/M/J/22

Explanation

Benedict's Test for Reducing Sugars Steps:

  • Glucose is a reducing sugar, reacts with Benedict's to give yellow precipitate in both M (direct) and N (after acid, no change).
  • Sucrose is non-reducing, remains blue in M; acid hydrolysis breaks it into glucose and fructose (reducing), giving yellow in N.
  • Mixture of glucose and sucrose gives blue in M (sucrose dominates, minimal reaction); in N, hydrolysis adds more reducing sugars, yielding red (stronger positive). Why C is correct:
  • Matches reducing property: glucose positive both ways; sucrose negative then positive; mixture weak/negative initially, strong positive after hydrolysis (color intensity reflects sugar amount). Why the others are wrong:
  • A: Omits glucose; mixture M blue correct but N yellow understates added sugars' effect.
  • B: Sucrose M yellow wrong (non-reducing); mixture M blue but omits glucose data.
  • D: Glucose N red wrong (acid doesn't increase its reducing power); all positives same intensity ignores hydrolysis boost. Final answer: C
Topic: Testing for biological molecules

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