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A Levels Biology (9700)•9700/13/M/J/20
Question 9 from 9700/13/M/J/20

Explanation

Enzyme Denaturation by Low pH

Steps:

  • Low pH increases H+ concentration, altering the charge balance in protein side chains.
  • Negatively charged R groups (like carboxylate) protonate, gaining positive charges.
  • This charge repulsion disrupts ionic bonds and hydrogen bonds maintaining 3D shape.
  • Resulting structural change denatures the enzyme, impairing function.

Why A is correct:

  • Protonation of negatively charged R groups (e.g., -COO- to -COOH) introduces repulsive forces, per principles of electrostatic interactions in protein folding.

Why the others are wrong:

  • B: Disulfide bonds are covalent and unaffected by pH; they require reducing agents to break.
  • C: Low pH decreases, not increases, hydrogen bonding by protonating potential donors/acceptors.
  • D: Hydrophilic groups' water affinity changes minimally; denaturation stems from charge disruption, not hydrophilicity.

Final answer: A

Topic: Factors that affect enzyme action

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