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A Levels Biology (9700)•9700/11/M/J/19
Question 13 from 9700/11/M/J/19

Explanation

Product inhibition limits enzyme activity at higher concentrations

Steps:

  • Identify glucose phosphate as the product of phosphorylase, which acts as an allosteric inhibitor.
  • Interpret iodine test: color disappearance measures glycogen breakdown rate; faster at low glucose phosphate.
  • Observe trend: at ≤25 mg dm⁻³ glucose phosphate, rapid decolorization indicates maximum rate.
  • Conclude: low inhibitor allows full enzyme activity, so enzyme concentration limits the rate.

Why C is correct:

  • In enzyme kinetics, without significant inhibition (at low product concentrations), the reaction rate reaches Vmax, limited by enzyme concentration per Michaelis-Menten model.

Why the others are wrong:

  • A: Maximum rate produces glucose phosphate, not converts to it; irrelevant to trend.
  • B: Glucose phosphate is inhibitory product, not substrate; substrate (glycogen) is constant.
  • D: Reaction is phosphorolysis, not hydrolysis; phrasing unrelated to observed trend.

Final answer: C

Topic: Factors that affect enzyme action

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