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O Levels Biology (5090)•5090/11/M/J/25
Question 24 from 5090/11/M/J/25

Explanation

Kidney Reabsorption Percentages

Steps:

  • Water reabsorption: (150 dm³ entering - 1.5 dm³ urine) / 150 dm³ × 100% = 99%.
  • Urea reabsorption: (50 g entering - 30 g urine) / 50 g × 100% = 40%.
  • Glucose: Normally fully reabsorbed in kidneys, so 100% (0 g in urine, though not listed).

Why A is correct:

  • Matches formula for reabsorption % = [(entering - excreted) / entering] × 100%, with glucose at 100% per renal physiology.

Why the others are wrong:

  • B: Water miscalculated as 98.5%; glucose 150% impossible (exceeds 100%).
  • C: Glucose value (1.50) and units wrong; ignores full reabsorption.
  • D: Inverts percentages (e.g., water 1% is urine amount, not reabsorbed).

Final answer: A

Topic: Urinary system

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