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O Levels Chemistry (5070)•5070/12/O/N/24
Question 20 from 5070/12/O/N/24

Explanation

Identifying Oxidized/Reduced Elements and Agents in Redox Reaction

Steps:

  • Fe oxidation state: +2 in Fe²⁺ to +3 in Fe³⁺, increases, so Fe oxidized.
  • S oxidation state in S₂O₈²⁻: (8O × -2 = -16; total -2 charge, so 2S = +14; each S +7); in SO₄²⁻: +6, decreases, so S reduced.
  • Oxidizing agent: species causing oxidation (reduced itself), S₂O₈²⁻ containing S.
  • Reducing agent: species causing reduction (oxidized itself), Fe²⁺ containing Fe.

Why C is correct:

  • Sulfur reduced (oxidation state +7 to +6), acts as oxidizing agent; iron oxidized (+2 to +3), acts as reducing agent, per redox definitions.

Why the others are wrong:

  • A: Iron oxidized, not reduced; SO₄²⁻ is product, not agent.
  • B: SO₄²⁻ not oxidizing agent (it's reduced product).
  • D: Sulfur reduced, not reducing agent; iron oxidized, not oxidizing agent.

Final answer: C

Topic: Redox

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