O Levels Chemistry (5070)•5070/11/O/N/23

Explanation
Calculate Na⁺ ions in Na₂SO₄ using molar mass, moles, and Avogadro's number
Steps:
- Molar mass of Na₂SO₄ = 2(23) + 32 + 4(16) = 142 g/mol.
- Moles of Na₂SO₄ = 30 / 142 ≈ 0.211 mol.
- Formula units = 0.211 × 6.02 × 10^{23} ≈ 1.27 × 10^{23}.
- Na⁺ ions = 2 × 1.27 × 10^{23} = 2.54 × 10^{23} (options imply ×10^{23}).
Why B is correct:
- Applies stoichiometry: 2 Na⁺ per Na₂SO₄ formula unit, times moles and Avogadro's number (6.02 × 10^{23} ions/mol).
Why the others are wrong:
- A: Assumes NaSO₄ (molar mass 119 g/mol), so 30/119 × 6.02 × 10^{23} ≈ 1.52 × 10^{23}.
- C: Equals Avogadro's number for 1 mol formula units, but 30 g is only 0.211 mol.
- D: Forgets to multiply by 2 (one Na⁺ per unit), so 0.211 × 6.02 × 10^{23} ≈ 1.27 × 10^{23} (rounded near 1.20 × 10^{23}).
Final answer: B
Topic: The mole and the Avogadro constant
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