O Levels Chemistry (5070)•5070/11/O/N/23
Explanation
Free Radical Chlorination of Propane Steps:
- Identify reaction type: Free radical substitution of alkane with halogen, requiring UV light for Cl-Cl bond homolysis.
- Evaluate statement 1: UV light provides activation energy by initiating radical formation, correct.
- Evaluate statement 2: C₃H₇Cl (chloropropane) has two structural isomers—1-chloropropane (primary) and 2-chloropropane (secondary), correct.
- Evaluate statement 3: Cl₂ is a neutral diatomic gas, not acidic (unlike HCl); it reacts with water to form mixed acids but is not classified as an acidic gas, incorrect.
Why B is correct:
- Statements 1 and 2 accurately describe the reaction mechanism and product isomers, per organic chemistry principles.
Why the others are wrong:
- A includes incorrect statement 3.
- C includes incorrect statement 3, excludes correct 2.
- D excludes correct 1, includes incorrect 3.
Final answer: B
Topic: Alkanes
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