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O Levels Chemistry (5070)•5070/11/O/N/23
Question 14 from 5070/11/O/N/23

Explanation

Reverse activation energy from forward Ea and ΔH

Steps:

  • Identify forward activation energy (Ea_forward) as the energy barrier from reactants to transition state: 447 kJ/mol.
  • Determine enthalpy change (ΔH) for the forward reaction as endothermic: +283 kJ/mol.
  • Apply the formula for reverse activation energy: Ea_reverse = Ea_forward - ΔH.
  • Calculate: 447 kJ/mol - 283 kJ/mol = 164 kJ/mol.

Why D is correct:

  • It matches Ea_reverse = Ea_forward - ΔH, per the definition of activation energies in reaction energy diagrams.

Why the others are wrong:

  • A: Negative activation energy is impossible, as it represents an energy barrier.
  • B: Likely a miscalculation, such as subtracting an incorrect value from Ea_forward.
  • C: Equals ΔH, not the reverse energy barrier.

Final answer: D

Topic: Exothermic and endothermic reactions

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