O Levels Chemistry (5070)•5070/12/O/N/22

Explanation
Ambiguous total volume prevents exact calculation Steps:
- Moles of NaOH = mass / molar mass = 15 g / 40 g/mol = 0.375 mol.
- NaOH dissolved in 250 cm³ water in a graduated flask, but total solution volume not specified (could exceed 250 cm³ if flask larger).
- Without total volume, NaOH concentration cannot be found.
- Moles of NaOH in 25 cm³ sample unknown, so volume of 0.50 mol/dm³ HCl for 1:1 neutralization undetermined.
Why B is correct:
- Not enough information to confirm any option, including B.
Why the others are wrong:
- A: Not enough information.
- C: Not enough information.
- D: Not enough information.
Final answer: Not enough information.
Topic: Acid–base titrations
Practice more O Levels Chemistry (5070) questions on mMCQ.me