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O Levels Chemistry (5070)•5070/11/O/N/22
Question 24 from 5070/11/O/N/22

Explanation

Reduction decreases oxidation state Steps:

  • Define reduction as a decrease in oxidation number (gain of electrons).
  • Examine oxidation states in each reaction or process.
  • Identify if any element's oxidation state decreases.
  • Select the option showing clear reduction.

Why D is correct:

  • In sand (SiO₂), silicon is +4; in silicon (Si), it is 0, so Si gains electrons (reduced) per the definition of reduction.

Why the others are wrong:

  • A: CaCO₃ decomposes to CaO + CO₂; Ca (+2), C (+4), and O (-2) oxidation states unchanged—no reduction.
  • B: Copper to brass is alloy formation (Cu + Zn)—physical mixture, no redox change.
  • C: Ethene to poly(ethene) is addition polymerization forming C-C bonds—oxidation states of C (-2 in both) unchanged.

Final answer: D

Topic: Redox

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