O Levels Chemistry (5070)•5070/12/O/N/21

Explanation
Precipitation tests identify Fe³⁺ and SO₄²⁻ in X Steps:
- Red-brown precipitate with NaOH indicates Fe³⁺ cation, as Fe(OH)₃ forms reddish-brown hydroxide.
- White precipitate with Ba(NO₃)₂ indicates SO₄²⁻ anion, as BaSO₄ is insoluble and white.
- White precipitate with dilute HNO₃ aligns with iron(III) sulfate behavior in acidic conditions, distinguishing from reducing ions like Cr²⁺ or Fe²⁺. Why D is correct:
- Iron(III) sulfate, Fe₂(SO₄)₃, yields red-brown Fe(OH)₃ with NaOH per solubility rules for metal hydroxides. Why the others are wrong:
- A: Chromium(II) sulfate yields blue Cr(OH)₂ with NaOH, not red-brown.
- B: Chromium(III) chloride yields gray-green Cr(OH)₃ with NaOH and no BaSO₄ with Ba(NO₃)₂, as Cl⁻ is soluble.
- C: Iron(II) sulfate yields green Fe(OH)₂ with NaOH, not red-brown. Final answer: D
Topic: Identification of ions and gases
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