mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
O Levels Chemistry (5070)•5070/11/O/N/21
Question 25 from 5070/11/O/N/21

Explanation

Percentage by mass of nitrogen in ammonium sulphate and nitrate Steps:

  • Identify chemical formulas: ammonium sulphate is (NH₄)₂SO₄; ammonium nitrate is NH₄NO₃.
  • Calculate molar mass of (NH₄)₂SO₄: (2×14) + (8×1) + 32 + (4×16) = 132 g/mol.
  • Calculate %N in (NH₄)₂SO₄: (28/132) × 100 = 21.2%.
  • Calculate %N in NH₄NO₃: molar mass = 80 g/mol, N mass = 28 g/mol, (28/80) × 100 = 35.0%. Why B is correct:
  • Provides accurate %N values matching the formula for percentage composition: (mass of N atoms / molar mass of compound) × 100. Why the others are wrong:
  • A: Both values incorrect—10.6% underestimates N in sulphate (wrong formula or atomic masses); 17.5% underestimates N in nitrate.
  • C: 21.2% correct for sulphate, but 17.5% wrong for nitrate (counts only one N atom).
  • D: Same as C, so incorrect for nitrate. Final answer: B
Topic: Relative masses of atoms and molecules

Practice more O Levels Chemistry (5070) questions on mMCQ.me