O Levels Chemistry (5070)•5070/11/O/N/21

Explanation
Electrode Products in Electrolysis
Steps:
- In electrolysis, cations move to the cathode (negative electrode) and are reduced; anions move to the anode (positive electrode) and are oxidized.
- For molten lead bromide (PbBr₂), the ions are Pb²⁺ and Br⁻, with no water present.
- At the anode, 2Br⁻ → Br₂ + 2e⁻, producing bromine gas.
- Verify other options against standard electrolysis rules for aqueous or molten electrolytes.
Why A is correct:
- Anions (Br⁻) are oxidized at the anode to form Br₂, as per the half-equation 2Br⁻ → Br₂ + 2e⁻ in molten salts without competing species.
Why the others are wrong:
- B: Positive ions (cations) are discharged at the cathode (negative electrode), not the anode.
- C: In aqueous NaCl, H₂O is reduced at the cathode to form H₂, not Na, due to water's lower reduction potential.
- D: Dilute H₂SO₄ electrolysis produces O₂ at the anode and H₂ at the cathode from water; SO₂ is not formed.
Final answer: A
Topic: Electrolysis
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