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O Levels Chemistry (5070)•5070/11/O/N/20
Question 37 from 5070/11/O/N/20

Explanation

Classifying ethanol reactions by type

Steps:

  • Reaction 1 converts ethanol (CH3CH2OH) to acetic acid (CH3COOH) using O2, a loss of hydrogen equivalent to oxidation.
  • Reaction 2 combines acetic acid (CH3COOH) and ethanol to form ethyl acetate (CH3COOCH2CH3) and water, defining esterification.
  • Reaction 3 breaks down ethanol to acetaldehyde (CH3CHO), CO2, and H2O, matching a fermentation decomposition process.
  • Match to options: Only D assigns oxidation to 1, esterification to 2, and fermentation to 3.

Why D is correct:

  • D accurately identifies reaction 1 as oxidation (alcohol oxidized to carboxylic acid via O2), 2 as esterification (acid-alcohol condensation to ester), and 3 as fermentation (ethanol breakdown yielding aldehyde, CO2, H2O).

Why the others are wrong:

  • A: Labels 1 as combustion, but combustion fully oxidizes to CO2/H2O, not partial to CH3COOH.
  • B: Labels 1 as combustion (incorrect, as above) and 3 as addition (no addition of groups occurs).
  • C: Labels 3 as addition (incorrect; it's decomposition, not bond addition).

Final answer: D

Topic: Alcohols

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