Esterification Reaction Forms Methyl Ethanoate Steps:

• Identify the target compound: CH3COOCH3 is methyl ethanoate (methyl acetate), an ester.
• Recall esterification: Carboxylic acid + alcohol → ester + water, where the ester formula combines the acid's acyl group (CH3CO-) and alcohol's alkyl group (-CH3).
• Match the acid: CH3CO- comes from ethanoic acid (CH3COOH).
• Match the alcohol: -CH3 comes from methanol (CH3OH).

Why none are correct:

• No option pairs ethanoic acid with methanol; all produce different esters.

Why the others are wrong:

• A: Forms ethyl ethanoate (CH3COOC2H5).
• B: Forms ethyl methanoate (HCOOC2H5).
• C: Forms propyl methanoate (HCOOC3H7).
• D: Forms methyl propanoate (CH3CH2COOCH3).

Not enough information: Options do not include the correct pair.

Final answer: None