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O Levels Chemistry (5070)•5070/12/O/N/19
Question 29 from 5070/12/O/N/19

Explanation

Cryolite's Role in Aluminum Electrolysis

Steps:

  • Identify the Hall-Héroult process: electrolysis of Al2O3 dissolved in molten cryolite (Na3AlF6) to produce aluminum.
  • Note cryolite lowers the melting point from 2050°C to ~950°C and increases electrolyte conductivity.
  • Evaluate anode reactions: carbon anodes oxidize to CO2, requiring replacement; cathodes do not.
  • Assess cryolite's function: it dissolves Al2O3, providing Al3+ ions for electrolysis without reacting with impurities.

Why A is correct:

  • Cryolite dissolves Al2O3, increasing the concentration and mobility of Al3+ ions in the electrolyte, enabling efficient electrolysis (per Faraday's laws of electrolysis).

Why the others are wrong:

  • B: Cryolite acts as a solvent, not a reactant for impurities; slag forms from fluxing agents like CaF2.
  • C: Carbon cathodes do not react significantly with oxygen; they are stable and long-lasting.
  • D: While anodes react with oxygen, this describes the anode, not cathode replacement.

Final answer: A

Topic: Electrolysis

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