Stoichiometric gas volume ratio in combustion reaction

Steps:

• Balanced equation: 2H₂S(g) + 3O₂(g) → 2SO₂(g) + 2H₂O(g).
• Volume ratio of H₂S to SO₂ is 2:2 (1:1) based on coefficients.
• 48 mL H₂S corresponds to 48 mL SO₂, as volumes are proportional to moles at same T and P.
• Excess O₂ ensures complete reaction without limiting SO₂ production.

Why C is correct:

• Avogadro's law states equal gas volumes at identical T and P contain equal moles, so 1:1 volume ratio matches 1:1 mole ratio.

Why the others are wrong:

• A (24 mL): Assumes 2:1 ratio, ignoring balanced coefficients.
• B (32 mL): Misapplies O₂ stoichiometry to SO₂ volume.
• D (96 mL): Doubles volume, confusing H₂S with total products.

Final answer: C