O Levels Chemistry (5070)•5070/11/O/N/19

Explanation
Electrophilic addition of Br₂ to the alkene double bond in butene
Steps:
- Butene (C₄H₈) is an alkene with a C=C bond that undergoes electrophilic addition with Br₂.
- Br₂ adds across the double bond following Markovnikov's rule, forming a vicinal dibromide.
- For 1-butene, addition yields 1,2-dibromobutane; for 2-butene, it yields 2,3-dibromobutane.
- The product is a saturated dibromobutane (C₄H₈Br₂) with Br atoms on adjacent carbons.
Why B is correct:
- B represents 1,2-dibromobutane, the direct product of anti addition to 1-butene's double bond per the mechanism of electrophilic addition.
Why the others are wrong:
- A is 1-bromobutane, a substitution product, not addition.
- C is 1,4-dibromobutane, requiring addition across non-adjacent carbons, impossible in this reaction.
- D is 2,2-dibromobutane, violating Markovnikov addition to form a geminal dihalide.
Final answer: B
Topic: Alkenes
Practice more O Levels Chemistry (5070) questions on mMCQ.me