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O Levels Chemistry (5070)•5070/11/O/N/18
Question 38 from 5070/11/O/N/18

Explanation

Esterification eliminates water from reactants

Steps:

  • Carboxylic acid general formula: RCOOH (carbons in R + 1C, hydrogens in R + 1H, 2O).
  • Alcohol general formula: R'OH (carbons in R', hydrogens in R' + 1H, 1O).
  • Ester formed: RCOOR' (all carbons from both, total H minus 2, total O minus 1) + H2O byproduct.
  • Water (H2O) removes 2H and 1O, leaving same total C in ester.

Why C is correct:

  • In esterification, RCOOH + R'OH → RCOOR' + H2O, conserving all C atoms while losing 2H and 1O to water.

Why the others are wrong:

  • A: Ester retains all C atoms, not fewer.
  • B: Ester retains all C atoms and loses 1O, not same O.
  • D: Ester loses 2H and 1O, not same totals.

Final answer: C

Topic: Carboxylic acids

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