O Levels Chemistry (5070)•5070/11/M/J/25

Explanation
Contact Process Conditions for SO₂ to SO₃
Steps:
- Identify catalyst: Vanadium(V) oxide accelerates the reaction without being consumed.
- Recall temperature: 400–450°C optimizes rate and yield for exothermic equilibrium.
- Recall pressure: 100–200 kPa (1–2 atm) shifts equilibrium right per Le Chatelier's principle.
- Match options: Select row with correct catalyst and pressure near 200 kPa.
Why D is correct:
- Vanadium(V) oxide is the standard catalyst; 200 represents ~200 kPa pressure, aligning with typical 1–2 atm to favor product formation.
Why the others are wrong:
- A: Iron is incorrect catalyst (V₂O₅ used); 2000 kPa is excessively high.
- B: Vanadium(V) oxide correct, but 200 likely °C (too low for reaction rate).
- C: Vanadium(V) oxide correct, but 2000 likely °C (impossibly high, would decompose reactants).
Final answer: D
Topic: Reversible reactions and equilibrium
Practice more O Levels Chemistry (5070) questions on mMCQ.me