O Levels Chemistry (5070)•5070/11/M/J/24

Explanation
Ethanol Production Conditions Steps:
- Identify ethanol from ethene via acid-catalyzed hydration requiring high temperature (300°C) and pressure (60 atm ≈ 6000 kPa) with steam.
- Identify ethanol from glucose via anaerobic fermentation using yeast at mild temperature (around 35°C) without oxygen.
- Evaluate A: Matches ethene hydration conditions exactly.
- Eliminate B, C, D by mismatched temperature, pressure, or oxygen presence.
Why A is correct:
- Hydration of ethene follows Markovnikov's rule under phosphoric acid catalysis with steam at 300°C and 6000 kPa to form ethanol efficiently.
Why the others are wrong:
- B: Yeast enzymes denature at 135°C, preventing fermentation.
- C: 60 kPa is too low for the reaction equilibrium to favor ethanol formation.
- D: Oxygen presence promotes aerobic respiration over alcoholic fermentation.
Final answer: A
Topic: Alcohols
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