Ionic bonding in Al₂O₃-like compound Steps:

• Identify valence electrons: X (2.8 likely simplifies to 2.8.3 for Al, valence 3) loses 3 e⁻; Y (2.6 for O, valence 6) gains 2 e⁻ to octet.
• Calculate electrons transferred: 2 X atoms lose 3 e⁻ each (6 e⁻ total); 3 Y atoms gain 2 e⁻ each (6 e⁻ total) for charge balance.
• Determine formula: Ratio 2:3 yields neutral ionic compound like Al₂O₃.
• Classify bonding: Metal (X) to nonmetal (Y) electron transfer forms ionic bonds.

Why B is correct:

• Matches ionic definition: Complete e⁻ transfer from electropositive X (loses 3 e⁻/atom) to electronegative Y (gains 2 e⁻/atom) in 2:3 ratio for stability.

Why the others are wrong:

• A: Covalent misclassifies; true transfer is ionic, not shared electrons.
• C: Reverses donor/acceptor roles; X loses, Y gains, not vice versa; covalent wrong.
• D: Both receiving electrons impossible; no donor, violates charge balance; ionic incorrect.

Final answer: B