O Levels Chemistry (5070)•5070/11/M/J/23

Explanation
Ionic bonding via electron transfer in MgCl₂
Steps:
- Magnesium (group 2) loses 2 valence electrons to achieve noble gas configuration, forming Mg²⁺.
- Chlorine (group 17) gains 1 electron per atom to form Cl⁻, requiring two Cl atoms per Mg.
- The compound formula is MgCl₂, with ionic bonds from electrostatic attraction between oppositely charged ions.
- Statement 1 is correct (Mg donates 2 e⁻, each Cl accepts 1); 2 is wrong (Cl⁻ has 1– charge); 3 is correct (Mg²⁺ has 2+ charge).
Why B is correct:
- B identifies statements 1 and 3, matching the electron transfer and ion charges in ionic bonding per octet rule.
Why the others are wrong:
- A includes 2, but Cl forms 1– ion, not 2–.
- C includes 2, but Cl charge is 1–, not 2–.
- D includes 4, but only 1 and 3 are correct; 4 is absent or incorrect.
Final answer: B
Topic: Ion and ionic bonds
Practice more O Levels Chemistry (5070) questions on mMCQ.me