O Levels Chemistry (5070)•5070/12/M/J/22

Explanation
Graham's law governs gas diffusion rates in the tube
Steps:
- Calculate molar masses: ethylamine (C₂H₅NH₂) = 45 g/mol; HCl = 36.5 g/mol.
- Apply Graham's law: diffusion rate ∝ 1/√(molar mass), so HCl (lighter) diffuses faster than ethylamine.
- HCl travels farther from its end, so the gases meet closer to the ethylamine end, forming the solid ring there.
- Position A is nearest the ethylamine source, matching the meeting point.
Why A is correct:
- HCl's faster diffusion shifts the reaction zone toward the slower-diffusing ethylamine end, per Graham's law.
Why the others are wrong:
- B: Midway assumes equal diffusion rates, ignoring molar mass differences.
- C: Closer to HCl end would require ethylamine to diffuse faster, which it doesn't.
- D: At HCl end ignores ethylamine's diffusion entirely.
Final answer: A
Topic: Diffusion
Practice more O Levels Chemistry (5070) questions on mMCQ.me