mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
O Levels Chemistry (5070)•5070/11/M/J/22
Question 38 from 5070/11/M/J/22

Explanation

Naming esters: alkyl from alcohol, alkanoate from acid chain

Steps:

  • Examine the ester structure: locate the -COO- linkage.
  • Count carbons in the acyl group (R-COO-): 4 carbons indicate butanoate.
  • Count carbons in the alkyl group (-OR'): 3 carbons indicate propyl.
  • Name as alkyl alkanoate: propyl butanoate.

Why C is correct:

  • The structure has a 4-carbon acyl chain (butanoate from butanoic acid) and a 3-carbon propyl group from propanol, per IUPAC ester naming.

Why the others are wrong:

  • A. butyl butanoate: alkyl is butyl (4 carbons), not propyl (3).
  • B. butyl propanoate: alkyl is butyl (4 carbons) and acyl is propanoate (3 carbons).
  • D. propyl propanoate: alkyl is correct (propyl), but acyl is propanoate (3 carbons), not butanoate (4).

Final answer: C

Topic: Naming organic compounds

Practice more O Levels Chemistry (5070) questions on mMCQ.me