O Levels Chemistry (5070)•5070/12/M/J/21

Explanation
Fractional distillation separates and purifies both gaseous components
Steps:
- Identify mixtures: A and C are soluble solid-liquid; B is insoluble solid-liquid; D is miscible gases.
- Assess methods: Crystallisation/evaporation recover pure solute but impure/contaminated solvent; filtration recovers pure liquid but wet solid; fractional distillation collects both by boiling points.
- Check purity of both: Only fractional distillation yields separate pure fractions for both components.
- Confirm D: Nitrogen (b.p. -196°C) and oxygen (b.p. -183°C) distill at different temperatures.
Why D is correct:
- Fractional distillation exploits boiling point differences (definition: repeated vaporization-condensation in a column) to collect pure nitrogen and oxygen streams from liquefied air.
Why the others are wrong:
- A: Crystallisation yields pure copper sulfate crystals, but mother liquor retains dissolved solute, so water remains impure.
- B: Filtration yields pure ethanol filtrate, but sand residue retains ethanol, requiring extra drying for purity.
- C: Evaporation yields pure salt residue, but water vaporizes and is not collected as a pure liquid sample.
Final answer: D
Topic: Separation and purification
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