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O Levels Chemistry (5070)•5070/12/M/J/20
Question 29 from 5070/12/M/J/20

Explanation

Rusting of Iron: Requirements and Prevention

Steps:

  • Rusting of iron is an electrochemical process requiring both oxygen (O₂) and water (H₂O) for oxidation and reduction reactions.
  • Sacrificial protection uses a more reactive metal than iron, which corrodes instead, preventing iron rusting.
  • Evaluate options: Check if conditions match O₂ + H₂O and if the metal is more reactive (e.g., magnesium in reactivity series above iron).
  • Select option with both correct conditions and suitable metal.

Why D is correct:

  • Rusting follows 4Fe + 3O₂ + 6H₂O → 4Fe(OH)₃, needing O₂ + H₂O; magnesium (Mg) is above Fe in reactivity series, so Mg oxidizes preferentially (Mg → Mg²⁺ + 2e⁻).

Why the others are wrong:

  • A: O₂ alone insufficient; copper below Fe, cannot protect sacrificially.
  • B: O₂ alone insufficient; magnesium correct for protection but conditions wrong.
  • C: H₂O alone insufficient; copper below Fe, cannot protect sacrificially.

Final answer: D

Topic: Corrosion of metals

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