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O Levels Chemistry (5070)•5070/11/M/J/20
Question 16 from 5070/11/M/J/20

Explanation

Electroplating setup requires metal ion electrolyte, plating metal as anode, and object as cathode

Steps:

  • Identify cathode as object to plate (steel key receives copper).
  • Identify anode as source of plating metal (pure copper dissolves to release Cu²⁺ ions).
  • Select electrolyte with metal ions (aqueous copper(II) sulfate provides Cu²⁺).
  • Arrange as electrolyte, anode (copper), cathode (steel key).

Why A is correct:

  • Follows Faraday's laws of electrolysis: Cu²⁺ ions from CuSO₄ solution reduce at cathode (steel key) to deposit Cu, while anode (copper) oxidizes to replenish ions.

Why the others are wrong:

  • B: Reverses electrodes; steel anode dissolves, plating iron onto copper cathode instead.
  • C: Sulfuric acid lacks Cu²⁺ ions, so no copper deposition occurs.
  • D: Sulfuric acid lacks Cu²⁺ ions, and reversed electrodes cause steel dissolution without copper plating.

Final answer: A

Topic: Electrolysis

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