O Levels Chemistry (5070)•5070/11/M/J/20

Explanation
Electroplating setup requires metal ion electrolyte, plating metal as anode, and object as cathode
Steps:
- Identify cathode as object to plate (steel key receives copper).
- Identify anode as source of plating metal (pure copper dissolves to release Cu²⁺ ions).
- Select electrolyte with metal ions (aqueous copper(II) sulfate provides Cu²⁺).
- Arrange as electrolyte, anode (copper), cathode (steel key).
Why A is correct:
- Follows Faraday's laws of electrolysis: Cu²⁺ ions from CuSO₄ solution reduce at cathode (steel key) to deposit Cu, while anode (copper) oxidizes to replenish ions.
Why the others are wrong:
- B: Reverses electrodes; steel anode dissolves, plating iron onto copper cathode instead.
- C: Sulfuric acid lacks Cu²⁺ ions, so no copper deposition occurs.
- D: Sulfuric acid lacks Cu²⁺ ions, and reversed electrodes cause steel dissolution without copper plating.
Final answer: A
Topic: Electrolysis
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