O Levels Chemistry (5070)•5070/11/M/J/19
Explanation
Ester naming: alkyl from alcohol, alkanoate from acid Steps:
- Parse name: "propyl methanoate" = propyl alcohol part + methanoate (from methanoic acid, HCOOH).
- Methanoate group: HCOO- (formyl from formic acid).
- Propyl group: CH3CH2CH2- (n-propyl).
- Combine: H-C(=O)-O-CH2CH2CH3.
- Check options: none match this formula.
Why D is correct:
- D does not match; it is ethyl propanoate (CH3CH2COO-CH2CH3), not propyl methanoate.
Why the others are wrong:
- A: Propyl ethanoate (CH3COO-CH2CH2CH3), wrong acid part (ethanoate, not methanoate).
- B: Methyl propanoate (CH3CH2COO-CH3), wrong alkyl and acid parts.
- C: Butanoic acid (CH3CH2CH2COOH), a carboxylic acid, not an ester.
Final answer: None of the above
Topic: Naming organic compounds
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