O Levels Chemistry (5070)•5070/11/M/J/19

Explanation
Reacting metal oxide with acid to form soluble salt
Steps:
- Identify copper(II) sulfate as CuSO4, needing a copper(II) source and sulfate ions without impurities.
- Evaluate options for reactions producing pure CuSO4 via displacement or acid-base.
- Eliminate non-reactive or impure methods using reactivity series and solubility rules.
- Select method yielding CuSO4 directly with filtration and crystallization for purity.
Why D is correct:
- CuO + H2SO4 → CuSO4 + H2O; insoluble oxide reacts completely with acid to form soluble CuSO4, filtered and crystallized pure.
Why the others are wrong:
- A: Cu below Zn in reactivity series; no displacement, no reaction.
- B: Cu metal inert to dilute H2SO4; no CuSO4 forms.
- C: No reaction between CuCO3 and Na2SO4; insoluble mixture, no CuSO4.
Final answer: D
Topic: Preparation of salts
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