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O Levels Chemistry (5070)•5070/11/M/J/19
Question 20 from 5070/11/M/J/19

Explanation

Identifying Oxidizing and Reducing Agents from Color Changes

Steps:

  • Acidified potassium manganate(VII) (KMnO4) is a purple oxidizing agent reduced to colorless Mn²⁺ by reducing agents.
  • Gas X causes decolorization, so X reduces KMnO4 and acts as a reducing agent.
  • Aqueous KI contains colorless I⁻ ions, oxidized to brown I₂ by oxidizing agents.
  • Gas Y causes browning, so Y oxidizes I⁻ and acts as an oxidizing agent.

Why B is correct:

  • B matches X reducing KMnO4 (MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O) and Y oxidizing KI (2I⁻ → I₂ + 2e⁻).

Why the others are wrong:

  • A: Labels both oxidizing; X reduces, not oxidizes.
  • C: Labels X oxidizing; X causes reduction of KMnO4.
  • D: Labels both reducing; Y causes oxidation of I⁻.

Final answer: B

Topic: Redox

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