Electrolysis of aluminum oxide in cryolite Steps:

• Identify J as the anode, which is the positive electrode where oxidation occurs in the Hall-Héroult process.
• Recognize K as the electrolyte mixture of molten aluminum and cryolite, which lowers the melting point for efficient conduction.
• Determine L as the raw material, aluminum oxide (bauxite ore), fed into the cell for extraction.
• Match these to option D, confirming the labels based on process components.

Why D is correct:

• In aluminum extraction, the positive electrode (anode) oxidizes oxygen ions, the electrolyte includes cryolite with dissolved aluminum species, and aluminum oxide is the ore source, as per the electrolytic reduction formula: 2Al₂O₃ → 4Al + 3O₂.

Why the others are wrong:

• A: Confuses electrode polarity; cathode (negative) produces aluminum, not anode.
• B: Misidentifies electrolyte as only cryolite and product as oxide; oxide is input, not output.
• C: Incorrectly labels electrolyte without aluminum component and swaps product roles.

Final answer: D