mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
O Levels Chemistry (5070)•5070/11/M/J/18
Question 30 from 5070/11/M/J/18

Explanation

Metal Reactivity and Stability Assessment

Steps:

  • Recall reactivity series: K > Na > Ca > Mg > Al > Zn > Fe > Sn > Pb > H > Cu > Ag > Au.
  • Test displacement: Higher reactivity metal displaces lower one from solution.
  • Evaluate acid reactions: Metals above H react with dilute acids to produce H2.
  • Assess thermal stability: Carbonate stability increases down group 1; transition metal carbonates decompose more readily.

Why D is correct:

  • Zinc, above copper in reactivity series, displaces Cu²⁺: Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s).

Why the others are wrong:

  • A: Copper, below H, does not react with dilute HCl to form H₂.
  • B: Sodium oxide requires electrolysis for reduction to Na; carbon reduces only less reactive metal oxides.
  • C: Zinc carbonate decomposes on heating (less stable) unlike stable sodium carbonate.

Final answer: D

Topic: Reactivity series

Practice more O Levels Chemistry (5070) questions on mMCQ.me