Precipitation of insoluble lead(II) sulfate via double displacement Steps:

• React solid lead(II) carbonate with aqueous sodium sulfate to form insoluble PbSO4 precipitate and soluble Na2CO3.
• Filter the mixture to separate the solid PbSO4 residue from the aqueous filtrate.
• Wash the residue with water to remove impurities like excess sodium sulfate.
• Dry the washed residue to obtain pure solid lead(II) sulfate.

Why B is correct:

• PbCO3(s) + Na2SO4(aq) → PbSO4(s) + Na2CO3(aq); insoluble PbSO4 precipitates and is isolated by washing/drying the residue, yielding pure solid without soluble byproducts contaminating it.

Why the others are wrong:

• A: Crystallizing the filtrate recovers soluble NaNO3, not insoluble PbSO4 residue.
• C: Solid Pb(NO3)2 dissolves in H2SO4 to form PbSO4(s), but crystallizing filtrate yields HNO3, not PbSO4.
• D: H2SO4 reacts with PbCO3 to evolve CO2 gas, risking incomplete reaction or impure residue without specified neutralization.

Final answer: B