Hall-Héroult Process for Aluminum Extraction Steps:

• Identify the electrolysis setup: molten aluminum oxide (Al₂O₃) is dissolved in cryolite (Na₃AlF₆) to lower the melting point.
• The positive electrode (anode) is carbon, where oxygen forms CO₂.
• The electrolyte mixture is Al₂O₃ + cryolite, enabling conduction at lower temperatures.
• Aluminum metal deposits at the negative electrode (cathode) and is collected as L.

Why C is correct:

• Matches the process: anode (J, positive) oxidizes oxygen; electrolyte (K, Al₂O₃ + cryolite) dissolves the ore; product (L, aluminum) forms at cathode.

Why the others are wrong:

• A: J is anode (positive), not negative; aluminum forms at negative electrode.
• B: K includes Al₂O₃ with cryolite, not cryolite alone; L is product aluminum, not Al₂O₃.
• D: K is electrolyte (Al₂O₃ + cryolite), not aluminum + cryolite; L is aluminum, not Al₂O₃.

Final answer: C