Hydrostatic pressure depends on liquid density and column height

Steps:

• Use formula P = ρgh, where g is constant, so compare ρh for each beaker base.
• From diagrams: assume A (X, low h), B (Y, low h), C (X, high h), D (Y, high h).
• Calculate ρh: A (1000 × low), B (900 × low), C (1000 × high), D (900 × high).
• C has maximum ρh, thus greatest pressure.

Why C is correct:

• C combines highest density (1000 kg/m³) with tallest height, maximizing P = ρgh.

Why the others are wrong:

• A: Same density as C but shorter height reduces ρh.
• B: Lower density than X and short height yield smallest ρh.
• D: Lower density than X offsets high height, resulting in ρh < C.

Final answer: C