O Levels Physics (5054)•5054/12/O/N/20

Explanation
Pulse interval = round-trip time + post-echo delay
Steps:
- Round-trip distance: 2 × 6000 m = 12000 m (noting likely typo for 600 m to match options).
- Round-trip time: 12000 m / 1500 m/s = 8 s.
- Add delay after receiving echo: 8 s + 2.0 s = 10 s.
- Thus, time from one pulse to the next is 10 s.
Why D is correct:
- The interval equals round-trip time (2 × depth / speed) plus the 2.0 s delay after echo reception, per sonar timing procedure.
Why the others are wrong:
- A: Assumes round-trip time of 2 s + 2 s delay, underestimating distance or overestimating speed.
- B: Assumes round-trip time of 4 s + 2 s delay, possible if depth halved.
- C: Assumes round-trip time of 6 s + 2 s delay, possible if speed reduced to ~1000 m/s.
Final answer: D
Topic: Sound
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